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Discussion Groups | MSP430 | sinewave pwm for msp430f2001
The purpose of this group is to foster exchange of information on the Texas Instruments MSP430 family of microcontrollers and related tools. Everyone welcome, all levels of familiarity/expertise.
sinewave pwm for msp430f2001 - yamsani madhu sudhan - Sep 10 23:55:12 2009
Hi,i am trying to generate sine wave based pwm for every 12degrees of sine =
wave for half wave of one complete cycle i am considering it as duty cycle =
and i am trying to update CCR1 register values with the given duty cycle va=
lues ie for every 12 degree increment and i am using peak value for duty cy=
cle of 60% ie CCR1=3D305 =A0and from there i want to linearly decrease in s=
ame decrement steps.But when i debug the program i am unable to get variabl=
e pwm for sinewave is there any mistake in my logic,if so please correct me=
.
thanks in advance....
=A0
=A0#include=20
const unsigned int duty[]=3D{122,183,244,305,244,183,122,61}
unsigned int i=3D0;
void main(void)
{
WDTCTL =3D WDTPW + WDTHOLD; // Stop WDT
P1DIR |=3D 0x04; // P1.2 output=20
P1SEL |=3D 0x04; // P1.2 TA1-out=20
CCR0 =3D 512-1; // PWM Period
CCTL0 =3D CCIE; //=20
CCTL1 =3D OUTMOD_7; // CCR1 reset/set
CCR1 =3D duty[i]; // CCR1 PWM duty cycle
TACTL =3D TASSEL_2 + MC_1; // SMCLK, up mode
_EINT();
for (;;)
{
_BIS_SR(CPUOFF); // Enter LPM0
_NOP(); // Required only for C-spy
}
}
#pragma vector=3DTIMERA0_VECTOR
__interrupt void Timer_A (void)
{
for(i=3D0;i<=3D7;i++)
CCR1=3Dduty[i];
}
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------------------------------------
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wave for half wave of one complete cycle i am considering it as duty cycle =
and i am trying to update CCR1 register values with the given duty cycle va=
lues ie for every 12 degree increment and i am using peak value for duty cy=
cle of 60% ie CCR1=3D305 =A0and from there i want to linearly decrease in s=
ame decrement steps.But when i debug the program i am unable to get variabl=
e pwm for sinewave is there any mistake in my logic,if so please correct me=
.
thanks in advance....
=A0
=A0#include
const unsigned int duty[]=3D{122,183,244,305,244,183,122,61}
unsigned int i=3D0;
void main(void)
{
WDTCTL =3D WDTPW + WDTHOLD; // Stop WDT
P1DIR |=3D 0x04; // P1.2 output=20
P1SEL |=3D 0x04; // P1.2 TA1-out=20
CCR0 =3D 512-1; // PWM Period
CCTL0 =3D CCIE; //=20
CCTL1 =3D OUTMOD_7; // CCR1 reset/set
CCR1 =3D duty[i]; // CCR1 PWM duty cycle
TACTL =3D TASSEL_2 + MC_1; // SMCLK, up mode
_EINT();
for (;;)
{
_BIS_SR(CPUOFF); // Enter LPM0
_NOP(); // Required only for C-spy
}
}
#pragma vector=3DTIMERA0_VECTOR
__interrupt void Timer_A (void)
{
for(i=3D0;i<=3D7;i++)
CCR1=3Dduty[i];
}
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------------------------------------
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Re: sinewave pwm for msp430f2001 - old_cow_yellow - Sep 11 13:28:42 2009
--- In m...@yahoogroups.com, yamsani madhu sudhan wrote:
>
> Hi,i am trying to generate sine wave based pwm for every 12degrees of sin=
e wave for half wave of one complete cycle i am considering it as duty cycl=
e and i am trying to update CCR1 register values with the given duty cycle =
values ie for every 12 degree increment and i am using peak value for duty =
cycle of 60% ie CCR1=3D305 =A0and from there i want to linearly decrease in=
same decrement steps.But when i debug the program i am unable to get varia=
ble pwm for sinewave is there any mistake in my logic,if so please correct =
me.
> thanks in advance....
> =A0
> =A0#include=20
> const unsigned int duty[]=3D{122,183,244,305,244,183,122,61}
> unsigned int i=3D0;
> void main(void)
> {
> WDTCTL =3D WDTPW + WDTHOLD; // Stop WDT
> P1DIR |=3D 0x04; // P1.2 output=20
> P1SEL |=3D 0x04; // P1.2 TA1-out=20
> CCR0 =3D 512-1; // PWM Period
> CCTL0 =3D CCIE; //=20
> CCTL1 =3D OUTMOD_7; // CCR1 reset/set
> CCR1 =3D duty[i]; // CCR1 PWM duty cycle
> TACTL =3D TASSEL_2 + MC_1; // SMCLK, up mode
> _EINT();
> for (;;)
> {
> _BIS_SR(CPUOFF); // Enter LPM0
> _NOP(); // Required only for C-spy
> }
> }
> #pragma vector=3DTIMERA0_VECTOR
> __interrupt void Timer_A (void)
> {
> for(i=3D0;i<=3D7;i++)
> CCR1=3Dduty[i];
> }
>=20
You are making the same mistake as in your previous posting.
Aug 25, MSG#42876:
=85 =85
while(1=3D=3D1)
{
if(CCR1
CCR1 =3D j+30; // CCR1 PWM duty cycle
}
else
{
CCR1=3D90;
}
=85 =85
It take time for the Timer to generate each PWM pulse. If you change the se=
tting before that pulse is generated, the previous setting is wiped out and=
has not effect.
BTW there are other things that do not make sense. Your duty[] does not hav=
e a sine wave at 12 degree increment. And you did not use duty[7].
------------------------------------
______________________________
Stellaris® MCU Family: New Parts, New Package, New Price.
(You need to be a member of msp430 -- send a blank email to msp430-subscribe@yahoogroups.com )
>
> Hi,i am trying to generate sine wave based pwm for every 12degrees of sin=
e wave for half wave of one complete cycle i am considering it as duty cycl=
e and i am trying to update CCR1 register values with the given duty cycle =
values ie for every 12 degree increment and i am using peak value for duty =
cycle of 60% ie CCR1=3D305 =A0and from there i want to linearly decrease in=
same decrement steps.But when i debug the program i am unable to get varia=
ble pwm for sinewave is there any mistake in my logic,if so please correct =
me.
> thanks in advance....
> =A0
> =A0#include
> const unsigned int duty[]=3D{122,183,244,305,244,183,122,61}
> unsigned int i=3D0;
> void main(void)
> {
> WDTCTL =3D WDTPW + WDTHOLD; // Stop WDT
> P1DIR |=3D 0x04; // P1.2 output=20
> P1SEL |=3D 0x04; // P1.2 TA1-out=20
> CCR0 =3D 512-1; // PWM Period
> CCTL0 =3D CCIE; //=20
> CCTL1 =3D OUTMOD_7; // CCR1 reset/set
> CCR1 =3D duty[i]; // CCR1 PWM duty cycle
> TACTL =3D TASSEL_2 + MC_1; // SMCLK, up mode
> _EINT();
> for (;;)
> {
> _BIS_SR(CPUOFF); // Enter LPM0
> _NOP(); // Required only for C-spy
> }
> }
> #pragma vector=3DTIMERA0_VECTOR
> __interrupt void Timer_A (void)
> {
> for(i=3D0;i<=3D7;i++)
> CCR1=3Dduty[i];
> }
>=20
You are making the same mistake as in your previous posting.
Aug 25, MSG#42876:
=85 =85
while(1=3D=3D1)
{
if(CCR1
CCR1 =3D j+30; // CCR1 PWM duty cycle
}
else
{
CCR1=3D90;
}
=85 =85
It take time for the Timer to generate each PWM pulse. If you change the se=
tting before that pulse is generated, the previous setting is wiped out and=
has not effect.
BTW there are other things that do not make sense. Your duty[] does not hav=
e a sine wave at 12 degree increment. And you did not use duty[7].
------------------------------------
______________________________
Stellaris® MCU Family: New Parts, New Package, New Price.
(You need to be a member of msp430 -- send a blank email to msp430-subscribe@yahoogroups.com )
Re: Re: sinewave pwm for msp430f2001 - yamsani madhu sudhan - Sep 14 2:05:35 2009
Then with out using software control how to use the code such that i will b=
e able to generate varibale pwm for sinewave.pls help me out in the logic..=
.thanks in advance
--- On Fri, 11/9/09, old_cow_yellow wrote:
From: old_cow_yellow
Subject: [msp430] Re: sinewave pwm for msp430f2001
To: m...@yahoogroups.com
Date: Friday, 11 September, 2009, 10:58 PM
=C2=A0=20
--- In msp430@yahoogroups. com, yamsani madhu sudhan wrote:
>
> Hi,i am trying to generate sine wave based pwm for every 12degrees of sin=
e wave for half wave of one complete cycle i am considering it as duty cycl=
e and i am trying to update CCR1 register values with the given duty cycle =
values ie for every 12 degree increment and i am using peak value for duty =
cycle of 60% ie CCR1=3D305 =C2=A0and from there i want to linearly decrease=
in same decrement steps.But when i debug the program i am unable to get va=
riable pwm for sinewave is there any mistake in my logic,if so please corre=
ct me.
> thanks in advance....
> =C2=A0
> =C2=A0#include=20
> const unsigned int duty[]=3D{122, 183,244,305, 244,183,122, 61}
> unsigned int i=3D0;
> void main(void)
> {
> WDTCTL =3D WDTPW + WDTHOLD; // Stop WDT
> P1DIR |=3D 0x04; // P1.2 output=20
> P1SEL |=3D 0x04; // P1.2 TA1-out=20
> CCR0 =3D 512-1; // PWM Period
> CCTL0 =3D CCIE; //=20
> CCTL1 =3D OUTMOD_7; // CCR1 reset/set
> CCR1 =3D duty[i]; // CCR1 PWM duty cycle
> TACTL =3D TASSEL_2 + MC_1; // SMCLK, up mode
> _EINT();
> for (;;)
> {
> _BIS_SR(CPUOFF) ; // Enter LPM0
> _NOP(); // Required only for C-spy
> }
> }
> #pragma vector=3DTIMERA0_ VECTOR
> __interrupt void Timer_A (void)
> {
> for(i=3D0;i<=3D7; i++)
> CCR1=3Dduty[i] ;
> }
>=20
You are making the same mistake as in your previous posting.
Aug 25, MSG#42876:
=E2=80=A6 =E2=80=A6
while(1=3D=3D1)
{
if(CCR1
CCR1 =3D j+30; // CCR1 PWM duty cycle
}
else
{
CCR1=3D90;
}
=E2=80=A6 =E2=80=A6
It take time for the Timer to generate each PWM pulse. If you change the se=
tting before that pulse is generated, the previous setting is wiped out and=
has not effect.
BTW there are other things that do not make sense. Your duty[] does not hav=
e a sine wave at 12 degree increment. And you did not use duty[7].
Keep up with people you care about with Yahoo! India Mail. Learn how.=
http://in.overview.mail.yahoo.com/connectmore
[Non-text portions of this message have been removed]
------------------------------------
(You need to be a member of msp430 -- send a blank email to msp430-subscribe@yahoogroups.com )
e able to generate varibale pwm for sinewave.pls help me out in the logic..=
.thanks in advance
--- On Fri, 11/9/09, old_cow_yellow
From: old_cow_yellow
Subject: [msp430] Re: sinewave pwm for msp430f2001
To: m...@yahoogroups.com
Date: Friday, 11 September, 2009, 10:58 PM
=C2=A0=20
--- In msp430@yahoogroups. com, yamsani madhu sudhan
>
> Hi,i am trying to generate sine wave based pwm for every 12degrees of sin=
e wave for half wave of one complete cycle i am considering it as duty cycl=
e and i am trying to update CCR1 register values with the given duty cycle =
values ie for every 12 degree increment and i am using peak value for duty =
cycle of 60% ie CCR1=3D305 =C2=A0and from there i want to linearly decrease=
in same decrement steps.But when i debug the program i am unable to get va=
riable pwm for sinewave is there any mistake in my logic,if so please corre=
ct me.
> thanks in advance....
> =C2=A0
> =C2=A0#include
> const unsigned int duty[]=3D{122, 183,244,305, 244,183,122, 61}
> unsigned int i=3D0;
> void main(void)
> {
> WDTCTL =3D WDTPW + WDTHOLD; // Stop WDT
> P1DIR |=3D 0x04; // P1.2 output=20
> P1SEL |=3D 0x04; // P1.2 TA1-out=20
> CCR0 =3D 512-1; // PWM Period
> CCTL0 =3D CCIE; //=20
> CCTL1 =3D OUTMOD_7; // CCR1 reset/set
> CCR1 =3D duty[i]; // CCR1 PWM duty cycle
> TACTL =3D TASSEL_2 + MC_1; // SMCLK, up mode
> _EINT();
> for (;;)
> {
> _BIS_SR(CPUOFF) ; // Enter LPM0
> _NOP(); // Required only for C-spy
> }
> }
> #pragma vector=3DTIMERA0_ VECTOR
> __interrupt void Timer_A (void)
> {
> for(i=3D0;i<=3D7; i++)
> CCR1=3Dduty[i] ;
> }
>=20
You are making the same mistake as in your previous posting.
Aug 25, MSG#42876:
=E2=80=A6 =E2=80=A6
while(1=3D=3D1)
{
if(CCR1
CCR1 =3D j+30; // CCR1 PWM duty cycle
}
else
{
CCR1=3D90;
}
=E2=80=A6 =E2=80=A6
It take time for the Timer to generate each PWM pulse. If you change the se=
tting before that pulse is generated, the previous setting is wiped out and=
has not effect.
BTW there are other things that do not make sense. Your duty[] does not hav=
e a sine wave at 12 degree increment. And you did not use duty[7].
Keep up with people you care about with Yahoo! India Mail. Learn how.=
http://in.overview.mail.yahoo.com/connectmore
[Non-text portions of this message have been removed]
------------------------------------
(You need to be a member of msp430 -- send a blank email to msp430-subscribe@yahoogroups.com )