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Dear all,

I am currently working on pic mcu, and I am using the External
Interrupt facility provided on the IO PORT B of the pic
microcontroller. I have written the code, which logically, I think is
correct. But, it is not producing the desired output.

Basically, I am trying to change the state of the io pins when the
interrupt occurs. When, I am sending the data via serial port, it is
arriving on the interrupt pin, but it is not changing the state of the
other IO pin as instructed by the code. A very small segment of my
code is given below:

void INT0_isr(void) {
//SelectPin = ~SelectPin;
SelectPin = 0; //select pin is an io pin
Delay10KTCYx(100);
INTCONbits.INT0IF =0; //clears the flag, so, that the interrupt can
occur again
transmit = receive;
SelectPin = 1;
}
I am quite confident that I have correctly used the INTCON registers
and the bits involved in that registers like GIE, INT01E etc.

Any suggestions or any advice from the past experiences will be really
appreciated.

Hope to hear from you soon.
Best Regards,
Musabbir

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> Dear all,
>
> I am currently working on pic mcu, and I am using the External
> Interrupt facility provided on the IO PORT B of the pic
> microcontroller. I have written the code, which logically, I think is
> correct. But, it is not producing the desired output.
>
> Basically, I am trying to change the state of the io pins when the
> interrupt occurs. When, I am sending the data via serial port, it is
> arriving on the interrupt pin, but it is not changing the state of the
> other IO pin as instructed by the code. A very small segment of my
> code is given below:
>
> void INT0_isr(void) {
> //SelectPin = ~SelectPin;
> SelectPin = 0; //select pin is an io pin
> Delay10KTCYx(100);
> INTCONbits.INT0IF =0; //clears the flag, so, that the interrupt can
> occur again
> transmit = receive;
> SelectPin = 1;
> }
> I am quite confident that I have correctly used the INTCON registers
> and the bits involved in that registers like GIE, INT01E etc.
>
> Any suggestions or any advice from the past experiences will be really
> appreciated.
>
> Hope to hear from you soon.
> Best Regards,
> Musabbir

Have you put any code at the interrupt vector to direct the processor to
your ISR? What PIC are you using? Also, are you doing a context save and
restore on going in to and out of the interrupt? If you're running a
debugger, you can set a breakpoint on the interrupt vector and single step
through your code.

Good luck!

Harold
--
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opportunities available!
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If you are using Port B "Interrupt on Change" feature, do not forget
to read the port in order to reset the change flag before returning
from your Interrupt Service Routine.

--- In p...@yahoogroups.com, "musabbirmajeed"
wrote:
>
> Dear all,
>
> I am currently working on pic mcu, and I am using the External
> Interrupt facility provided on the IO PORT B of the pic
> microcontroller. I have written the code, which logically, I think is
> correct. But, it is not producing the desired output.
>
> Basically, I am trying to change the state of the io pins when the
> interrupt occurs. When, I am sending the data via serial port, it is
> arriving on the interrupt pin, but it is not changing the state of the
> other IO pin as instructed by the code. A very small segment of my
> code is given below:
>
> void INT0_isr(void) {
> //SelectPin = ~SelectPin;
> SelectPin = 0; //select pin is an io pin
> Delay10KTCYx(100);
> INTCONbits.INT0IF =0; //clears the flag, so, that the interrupt can
> occur again
> transmit = receive;
> SelectPin = 1;
> }
> I am quite confident that I have correctly used the INTCON registers
> and the bits involved in that registers like GIE, INT01E etc.
>
> Any suggestions or any advice from the past experiences will be really
> appreciated.
>
> Hope to hear from you soon.
> Best Regards,
> Musabbir
>

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