> Solved it myself. I transfered the value over accomulator.
> MOV A, R5
> MOV R0, A
If you want to preserve the content of the accumulator, you might as
well use "MOV R0,5" - the 5 will be used as memory address 5, which in
fact is R5 in register bank 0. This method is fine as long as you know
which register bank you are using. Some assemblers already have
predefined constants for these memory addresses (like "AR5" in mine,
standing for "absolutely addressed R5").
Tilmann
Reply by Josip●February 23, 20092009-02-23
Solved it myself. I transfered the value over accomulator.
MOV A, R5
MOV R0, A
I was afraid I would have to use RAM to make the transfer, but this solution
suits me fine.
Enough talking to myself...
Bye
"Josip" <sorry.no@can.do> wrote in message
news:gntp5j$qqg$1@ss408.t-com.hr...
> Just a quick question regarding 8051 assembly programming:
>
> I need to transfer a value from register R5 to R0, so I can use R5 for
> something else. I tried MOV R0, R5 but it fails.
> I know this is begginer's question, but I guess it wouldn't take to much
> time for someone experienced to answer this.
>
> Thanks
> Josip
Reply by Josip●February 23, 20092009-02-23
Just a quick question regarding 8051 assembly programming:
I need to transfer a value from register R5 to R0, so I can use R5 for
something else. I tried MOV R0, R5 but it fails.
I know this is begginer's question, but I guess it wouldn't take to much
time for someone experienced to answer this.
Thanks
Josip