Ken Barlow wrote:
>>>Is there a way of forcing all alignment onto four byte boundaries?  I've
>>>looked through the GCC and LD docs and can find switches for other
>>>targets, but not the ARM.
>>
>>Compiler does this automatically.  If you, say, have the structure
>>
>>struct {
>>     uint8_t   one;
>>     uint32_t  two;
>>} foo;
>>
>>then foo.two will always be word aligned.
>>
>>What are your trying to do?  If you would post a snippet of your data
>>structure it might be easier to help.
>>
> 
> 
> Hi again,
> 
> The structure is like this:
> 
> struct {
>     uint8 aByte;
>     uint8 aByteArray[ 64 ];
> } foo;
> 
> Hence my problem - the aByteArray is used as a generic buffer that can hold
> anything.  I was putting 32bit words into it, and as a byte array  there is
> no way of the compiler knowing that I wanted it 32bit aligned - a bit silly
> now I come to look at it but sometimes it takes somebody else to point out
> you are doing something daft ;-)
> 


I think you can force gcc to align the buffer using:

struct {
     uint8 aByte;
     uint8 aByteArray[ 64 ] __attribute__ ((aligned (4)));
} foo;

(untested)


--
Arne

On Fri, 28 May 2004 18:03:02 +0100, "Ken Barlow"
<ken_barlow@hotmail.com.NOSPAM> wrote:

>Hi again,
>
>The structure is like this:
>
>struct {
>    uint8 aByte;
>    uint8 aByteArray[ 64 ];
>} foo;
>
>Hence my problem - the aByteArray is used as a generic buffer that can hold
>anything.  I was putting 32bit words into it, and as a byte array  there is
>no way of the compiler knowing that I wanted it 32bit aligned - a bit silly
>now I come to look at it but sometimes it takes somebody else to point out
>you are doing something daft ;-)

   There seems to be something a bit kludgy about what I'm about to
suggest (I'm not sure why, except there's this Bogus_Variable defined
but never used), but could you use a union of a 4-byte 'bogus' unused
varuable with the aByteArray, to make the compiler align it? Like
this:

struct {
    uint8 aByte;
    union { 
       uint32 Bogus_Variable;
       uint8 aByteArray[ 64 ];
   }
} foo;

   There seems like there ought to be another way to do it, perhaps
with a compiler-specific #pragma, but this should work with any
compiler.

>In answer to the other question:  I'm not using -fpack-struct.
>
>Thanks again.

-----
http://mindspring.com/~benbradley

On Fri, 28 May 2004 18:03:02 +0100, Ken Barlow 
<ken_barlow@hotmail.com.NOSPAM> wrote:

> The structure is like this:
>
> struct {
>     uint8 aByte;
>     uint8 aByteArray[ 64 ];
> } foo;

Fine, this explains why the value you read is rotated right by one byte.

You might probably need to do something like

struct {
     uint8  aByte;
     union {
         uint32  aWordArray[16];
         uint8   aByteArray[64];
     } u;
} foo;

In this case foo.u.aWordArray[x] is guaranteed to be word aligned, as the 
whole union will be.


HTH,

   Vadim

In article <cjKtc.4668$Dm2.2182@front-1.news.blueyonder.co.uk>, Ken Barlow wrote:

> struct {
>     uint8 aByte;
>     uint8 aByteArray[ 64 ];
> } foo;
> 
> Hence my problem - the aByteArray is used as a generic buffer that can hold
> anything.  I was putting 32bit words into it, and as a byte array  there is
> no way of the compiler knowing that I wanted it 32bit aligned - a bit silly
> now I come to look at it but sometimes it takes somebody else to point out
> you are doing something daft ;-)

You probably need to use memcpy() to copy data to/from your
buffer.  You could force alignment of the beginning of the
array, but things will still fall apart if you use type-punned
pointers to put multiple things of differing sizes into the
buffer.

> In answer to the other question:  I'm not using -fpack-struct.

-- 
Grant Edwards                   grante             Yow!  Nice decor!
                                  at               
                               visi.com            

> > Is there a way of forcing all alignment onto four byte boundaries?  I've
> > looked through the GCC and LD docs and can find switches for other
> > targets, but not the ARM.
>
> Compiler does this automatically.  If you, say, have the structure
>
> struct {
>      uint8_t   one;
>      uint32_t  two;
> } foo;
>
> then foo.two will always be word aligned.
>
> What are your trying to do?  If you would post a snippet of your data
> structure it might be easier to help.
>

Hi again,

The structure is like this:

struct {
    uint8 aByte;
    uint8 aByteArray[ 64 ];
} foo;

Hence my problem - the aByteArray is used as a generic buffer that can hold
anything.  I was putting 32bit words into it, and as a byte array  there is
no way of the compiler knowing that I wanted it 32bit aligned - a bit silly
now I come to look at it but sometimes it takes somebody else to point out
you are doing something daft ;-)

In answer to the other question:  I'm not using -fpack-struct.

Thanks again.

On 2004-05-28, Ken Barlow <ken_barlow@hotmail.com.NOSPAM> wrote:

>>> The code generated to load R0 is: LDR R0, [R2,#0004] where R2
>>> in this case has the same value as R4 in the previous case -
>>> but the value loaded into R0 is 0x25400006 - which is all the
>>> correct digits but in the wrong order!
>>
>> Check that R2 is word aligned.  If it is not, the loaded value will be
>> rotated.
>>
>> Your address seems to have bit 0 set.  If this is the case -- the compiler
>> is doing something really nasty.
>
> Thanks for the advice - the variable being assigned is
> actually part of a structure (I simplified the example).
> Ensuring the variable started on a 4byte boundary fixed the
> problem.  Pointer alignment troubles!
>
> Is there a way of forcing all alignment onto four byte
> boundaries?  I've looked through the GCC and LD docs and can
> find switches for other targets, but not the ARM.

The compiler will properly align all variables and structure
fields unless you tell it to do otherwise.

IOW, you had to write code that does something bad to get such
an alignment problem (most likely typecasting a pointer or
using a packed struct). You're probably better off not doing
"bad" things rather than forcing the alignment of everything to
a word boundary. If you explain what it is you're actually
trying to do, somebody can show you how to do it the "good"
way.

-- 
Grant Edwards                   grante             Yow!  ... I'm IMAGINING a
                                  at               sensuous GIRAFFE, CAVORTING
                               visi.com            in the BACK ROOMof a KOSHER
                                                   DELI --

Ken Barlow wrote:
>Thanks for the advice - the variable being assigned is actually part of a
>structure (I simplified the example).  Ensuring the variable started on a
>4byte boundary fixed the problem.  Pointer alignment troubles!
>
>Is there a way of forcing all alignment onto four byte boundaries?  I've
>looked through the GCC and LD docs and can find switches for other targets,
>but not the ARM.

Are you using the compiler switch '-fpack-struct' ?
If so you must manually ensure the correct padding is used.

Andy

On Fri, 28 May 2004 16:28:13 +0100, Ken Barlow 
<ken_barlow@hotmail.com.NOSPAM> wrote:

> Is there a way of forcing all alignment onto four byte boundaries?  I've
> looked through the GCC and LD docs and can find switches for other 
> targets, but not the ARM.

Compiler does this automatically.  If you, say, have the structure

struct {
     uint8_t   one;
     uint32_t  two;
} foo;

then foo.two will always be word aligned.

What are your trying to do?  If you would post a snippet of your data 
structure it might be easier to help.


   Vadim

> > The code generated to load R0 is: LDR R0, [R2,#0004]
> > where R2 in this case has the same value as R4 in the previous case -
but
> > the value loaded into R0 is 0x25400006 - which is all the correct digits
> > but in the wrong order!
>
> Check that R2 is word aligned.  If it is not, the loaded value will be
> rotated.
>
> Your address seems to have bit 0 set.  If this is the case -- the compiler
> is doing something really nasty.
>
> HTH,
>    Vadim

Thanks for the advice - the variable being assigned is actually part of a
structure (I simplified the example).  Ensuring the variable started on a
4byte boundary fixed the problem.  Pointer alignment troubles!

Is there a way of forcing all alignment onto four byte boundaries?  I've
looked through the GCC and LD docs and can find switches for other targets,
but not the ARM.

Thanks again!

On Fri, 28 May 2004 10:33:56 +0100, Ken Barlow 
<ken_barlow@hotmail.com.NOSPAM> wrote:

> The code generated to load R0 is: LDR R0, [R2,#0004]
> where R2 in this case has the same value as R4 in the previous case - but
> the value loaded into R0 is 0x25400006 - which is all the correct digits 
> but in the wrong order!

Check that R2 is word aligned.  If it is not, the loaded value will be 
rotated.

Your address seems to have bit 0 set.  If this is the case -- the compiler 
is doing something really nasty.

HTH,
   Vadim