"jason_terhune" wrote:
> Hello,
> I am very new to the 68HC12. I am in a class where we use the 68HC12 along
> with an IDE from P&E Microcomputer Systems, Inc. I have only written some
> basic if-else and while loops at this point. The latest problem I've had
> is using the instruction FDIV. The code I have so far is:
>
> LDD #$04
> LDX #$0A
> FDIV
> STX $0800 ; the answer I get in acc. X is 6666
>
> I know this is the correct answer since 2^-2 + 2^-3 + 2^-6 + 2^-7 + 2^-10
> + 2^-11 + 2^-14 + 2^-15 = .4
FDIV works like this D*$10000 / X . $4000000/$A00=$6666
>
> I am just wondering how I can multiply numbers by the .4 now? How can I
> represent .4 in a register?
LDD #multiplier
LDY #$6666
EMUL ;; 32bit product in Y:D
;; to divide by $10000 just take upper word of
the product:
STY result
Don't know if I understand your question about representing .4 in register.
If you want it to be something like result of 4 FDIV 10, then 4*$10000 / 10
>
> My goal is to use the number generated by the FDIV, and set it up in a
> loop to add to itself 10 times. Each time multiplying the result to the
> slope of a line...
This is also not fully clear.
>
> something like:
> .4(250) = 100 ----> store in memory $5000 and $6000
> .8(250) = 200 ----> store in memory $5001 and $6001
> 1.2(250) = 300 ----> store in memory $5002 and $6002
> 1.6(250) = 400 ----> store in memory $5003 and $6003
> and so on...
>
> Any help would be great. Thanks!
Edward