Chris Hills wrote:
>
... snip ...
> 
> /* how to convert ads to iar? */
> 
> #include <stdio.h>
> 
> int main(void )
> {
>   char one = 'a';
>   char two  ='d';
>   char three ='s';
>   char four  = 8;
>   char five = 3;
>   char six =1;
>   printf("%c %c %c \n", one, two, three);
> 
>   one = one + four;
>   two = two -five;
>   three = three - six;
>   printf("%c %c %c \n", one, two, three);
> 
>   return 0;
> }

Fails if the char. set is ebcdic (or some others) :-)

-- 
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 <http://www.securityfocus.com/columnists/423>
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                        cbfalconer at maineline dot net



-- 
Posted via a free Usenet account from http://www.teranews.com

On 21/05/2007 Chris Hills wrote:

> In article <f2sl6q.1o4.1@stefan.msgid.phost.de>, Stefan Reuther
> <stefan.news@arcor.de> writes
> > Chris Hills wrote:
> > > /* "keil" to "iar" will need some thinking about */
> > 
> > No problem.
> > 
> > #include <stdio.h>
> > int main() {
> >  char x[6];
> >  fgets(x, 6, stdin);
> >  printf("%c%c%c\n", x[2], x[1] - 4, x[0]+x[3]-x[1]);
> >  return 0;
> > }
> > 
> > Even works for upper-case :-)
> 
> 
> Any one want to try "windriver" to" iar"? :-)

#include <stdio.h>
int main() {
  char x[11];
  char *p = &x[1];
  fgets(x, 11, stdin);
  printf("%c", *p);
  p += 2;
  printf("%c", *p - 3);
  p += 5;
  printf("%c\n", *p);
  return 0;
}


-- 
John B

"lzh08" <cppcpldfpga@gmail.com> wrote in message 
news:1179732737.322113.259380@b40g2000prd.googlegroups.com...
> who could tell me?thx

Without knowing what you want to convert then no-one can help you. If 
you've written ANSI C then everything will run just dandy. However, if 
you've used compiler extensions then you need to find the appropriate 
extensions under IAR. Their support people are very helpful (at a price) 
and respond quickly.

If you write code that conforms to standards and liberally document the 
places where it doesn't then you won't get this problem in the future. 

In article <f2sl6q.1o4.1@stefan.msgid.phost.de>, Stefan Reuther 
<stefan.news@arcor.de> writes
>Chris Hills wrote:
>> /* "keil" to "iar" will need some thinking about */
>
>No problem.
>
>#include <stdio.h>
>int main() {
>   char x[6];
>   fgets(x, 6, stdin);
>   printf("%c%c%c\n", x[2], x[1] - 4, x[0]+x[3]-x[1]);
>   return 0;
>}
>
>Even works for upper-case :-)


Any one want to try "windriver" to" iar"? :-)



-- 
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\
\/\/\/\/\ Chris Hills  Staffs  England     /\/\/\/\/
/\/\/ chris@phaedsys.org      www.phaedsys.org \/\/\
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

Chris Hills wrote:
> /* "keil" to "iar" will need some thinking about */

No problem.

#include <stdio.h>
int main() {
   char x[6];
   fgets(x, 6, stdin);
   printf("%c%c%c\n", x[2], x[1] - 4, x[0]+x[3]-x[1]);
   return 0;
}

Even works for upper-case :-)


  Stefan

In article <43n8i4-p4o.ln1@fenelon.com>, Pete Fenelon 
<pete@stratos.fenelon.com> writes
>Vladimir Vassilevsky <antispam_bogus@hotmail.com> wrote:
>>
>>
>> lzh08 wrote:
>>> who could tell me?thx
>>>
>>
>> ADS is RF design suit.
>
>Nope. ARM Developer Suite. ;)
>

I think he knows that. He is just being perverse like the rest of us.

Anyway I provided a hard coded solution in C using EWB :-)


-- 
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\
\/\/\/\/\ Chris Hills  Staffs  England     /\/\/\/\/
/\/\/ chris@phaedsys.org      www.phaedsys.org \/\/\
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

In article <h8RSzJGOTaUGFA1z@phaedsys.demon.co.uk>, Chris Hills
<chris@phaedsys.org> writes
>In article <1179732737.322113.259380@b40g2000prd.googlegroups.com
>>, lzh08 <cppcpldfpga@gmail.com> writes
>>who could tell me?thx

/* how to convert ads to iar? */
/* the invoice is in the post */
/* next converting ghs to iar */
/* "keil" to "iar" will need some thinking about */
/* Some one else can do "windriver" to "iar" :-) */

#include <stdio.h>

int main(void )
{

   char one = 'a';
  char two  ='d';
  char three ='s';

  char four  = 8;
  char five = 3;
  char six =1;

  printf("%c %c %c \n", one, two, three);

  one = one + four;
  two = two -five;
  three = three - six;

  printf("%c %c %c \n", one, two, three);

  return 0;
}



-- 
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\
\/\/\/\/\ Chris Hills  Staffs  England     /\/\/\/\/
/\/\/ chris@phaedsys.org      www.phaedsys.org \/\/\
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

Vladimir Vassilevsky <antispam_bogus@hotmail.com> wrote:
> 
> 
> lzh08 wrote:
>> who could tell me?thx
>> 
> 
> ADS is RF design suit.

Nope. ARM Developer Suite. ;)

pete
-- 
pete@fenelon.com "how many clever men have called the sun a fool?"

In article <1179732737.322113.259380@b40g2000prd.googlegroups.com>,
lzh08 <cppcpldfpga@gmail.com> writes
>who could tell me?thx
>


Run this.... not pretty but it converts ads to iar ! (I even used an IAR
EWB to do it :-)


#include <stdio.h>

int main(void )
{

  char one = 'a';
  char two  ='d';
  char three ='s';

  char four  = 8;
  char five = 3;
  char six =1;

  printf("%c %c %c \n", one, two, three);

  one = one + four;
  two = two -five;
  three = three - six;

  printf("%c %c %c \n", one, two, three);

  return 0;
}
-- 
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\
\/\/\/\/\ Chris Hills  Staffs  England     /\/\/\/\/
/\/\/ chris@phaedsys.org      www.phaedsys.org \/\/\
\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/

lzh08 wrote:
> who could tell me?thx
> 

ADS is RF design suit.
IAR is embedded workbench.
It wouldn't be too simple to make a conversion...

Vladimir Vassilevsky

DSP and Mixed Signal Design Consultant

http://www.abvolt.com