Started by October 5, 2011
I have code that is not working for the MC68HC12, it takes 0-5V into the
ADC and does some math to convert to revolutions per second and outputs
to 2 LED's. Could someone analyze the code to tell me in general what
might be wrong with the code. Some where I've think I've made a basic
mistake, I have not used the ADC before. I get not display on LED's.

The code, sorry don't know how to wrap the code with formatting.

include 'MC9S12C128.inc'
org \$800
movb #\$FF, DDRB
movb #\$C0, ATDCTL2
movb #\$00, ATDCTL3
movb #\$00, ATDCTL4
ldaa #1
Wait deca
bne Wait
movb #\$20, ATDCTL5
ldab ATDDR0H ;AB will hold the input

loop clra ;clear AA- AB holds converted input
ldab #\$80 ;test data -to be commented out
ldx #51 ;relationship between digital number
and BCD
idiv ;as defined in prelab
stx holder ;holder holds the ones place
ldaa #10 ;there will be a remainder. Want at
least 1 decimal point accuracy
mul
ldx #51 ;repeat dividing by 51
idiv
stx holder2 ;holder2 holds the tenths place
ldd holder ;what follows is multiplying both the
ones and teneths place by (18/5)
ldy #18 ;as shown in pre-lab work
emul
std holder
ldd holder2
ldy #18
emul
std holder2
ldd holder
ldx #5
idiv
stx holder
ldd holder2
ldx #5
idiv
stx holder2
ldd holder2 ;we then want to divide holder2
(tenths place) by 10 and add it to holder
ldx #10 ;in order to get 1 number with which
to continue calculation of RSP
idiv
xgdx
std Va
ldd #14 ;we want to add 1.4 to Va, per pre-lab
work. divide 14 by 10 to achieve this
ldx #10
idiv
stx holder
std holder2 ;remainder stored in holder2
ldd Va
std Va
ldd holder2
ldx #10
idiv
ldd Va
std Va
ldy #2 ;multiply by 2
emul
std Va
ldd #46 ;multiply by .46 = (46/100)
ldx #100
idiv
stx Va ;Va now contains RPS

ldd Va
cpd #10
bge output1
ldaa #00
output1 ldd Va ;checks value of tens place of RPS
ldx #10
idiv
stx tensplace
ldd tensplace
cpd #1
beq one1
ldd tensplace
cpd #2
beq two1
ldd tensplace
cpd #3
beq three1
ldd tensplace
cpd #4
beq four1
ldd tensplace
cpd #5
beq five1
ldd tensplace
cpd #6
beq six1
ldd tensplace
cpd #7
beq seven1
ldd tensplace
cpd #8
beq eight1
ldd tensplace
beq nine1
ldaa #00

one1 ldaa one ;will load appropriate hex number to
have 7-seg display output
two1 ldaa two ;appropriate number
three1 ldaa three
four1 ldaa four
five1 ldaa five
six1 ldaa six
seven1 ldaa seven
eight1 ldaa eight
nine1 ldaa nine
staa tensplace

ldd Va ;checks value of tens place of RPS
ldx #10
idiv
stx onesplace
ldd onesplace
cpd #1
beq one2
ldd onesplace
cpd #2
beq two2
ldd onesplace
cpd #3
beq three2
ldd onesplace
cpd #4
beq four2
ldd onesplace
cpd #5
beq five2
ldd onesplace
cpd #6
beq six2
ldd onesplace
cpd #7
beq seven2
ldd onesplace
cpd #8
beq eight2
ldd onesplace
beq nine1
ldaa #00

one2 ldaa one ;will load appropriate hex number to
have 7-seg display output
two2 ldaa two ;appropriate number
three2 ldaa three
four2 ldaa four
five2 ldaa five
six2 ldaa six
seven2 ldaa seven
eight2 ldaa eight
nine2 ldaa nine
staa onesplace
movb #\$7C, DDRCAN ;configure portcan for output (from
textbook)
movb #\$FF, DDRP ;configure portp for output
movb tensplace, PORTP ;place tens-place output code on
portp
movb #\$40, PORTCAN ;activate pcan6 so that led will
illuminate with tensplace digit
movb #\$30, PORTCAN ;activate pcan5
movb onesplace, PORTP ;illuminate ones-place output code
lbra loop

swi

holder rmb 2
holder2 rmb 2
Va rmb 2
tensplace rmb 1
onesplace rmb 1
zero equ \$7E
one equ \$30
two equ \$6D
three equ \$79
four equ \$33
five equ \$5B
six equ \$5F
seven equ \$70
eight equ \$7F
nine equ \$7B
PORTP equ \$56
PORTCAN equ \$13E
DDRCAN equ \$13F

eight1 ldaa #eight
bra nine1b
nine1 ldaa #nine
nine1b staa tensplace

Then study the instruction set some more.

> 6... wrote:
>
> I have code that is not working for the MC68HC12, it takes 0-5V into the
> ADC and does some math to convert to revolutions per second and outputs
> to 2 LED's. Could someone analyze the code to tell me in general what
> might be wrong with the code. Some where I've think I've made a basic
> mistake, I have not used the ADC before. I get not display on LED's.
>
> The code, sorry don't know how to wrap the code with formatting.
>
> include 'MC9S12C128.inc'
> org \$800
> movb #\$FF, DDRB
> movb #\$C0, ATDCTL2
> movb #\$00, ATDCTL3
> movb #\$00, ATDCTL4
> ldaa #1
> Wait deca
> bne Wait
> movb #\$20, ATDCTL5
> ldab ATDDR0H ;AB will hold the input
>
> loop clra ;clear AA- AB holds converted input
> ldab #\$80 ;test data -to be commented out
> ldx #51 ;relationship between digital number
> and BCD
> idiv ;as defined in prelab
> stx holder ;holder holds the ones place
> ldaa #10 ;there will be a remainder. Want at
> least 1 decimal point accuracy
> mul
> ldx #51 ;repeat dividing by 51
> idiv
> stx holder2 ;holder2 holds the tenths place
> ldd holder ;what follows is multiplying both the
> ones and teneths place by (18/5)
> ldy #18 ;as shown in pre-lab work
> emul
> std holder
> ldd holder2
> ldy #18
> emul
> std holder2
> ldd holder
> ldx #5
> idiv
> stx holder
> ldd holder2
> ldx #5
> idiv
> stx holder2
> ldd holder2 ;we then want to divide holder2
> (tenths place) by 10 and add it to holder
> ldx #10 ;in order to get 1 number with which
> to continue calculation of RSP
> idiv
> xgdx
> std Va
> ldd #14 ;we want to add 1.4 to Va, per pre-lab
> work. divide 14 by 10 to achieve this
> ldx #10
> idiv
> stx holder
> std holder2 ;remainder stored in holder2
> ldd Va
> std Va
> ldd holder2
> ldx #10
> idiv
> ldd Va
> std Va
> ldy #2 ;multiply by 2
> emul
> std Va
> ldd #46 ;multiply by .46 = (46/100)
> ldx #100
> idiv
> stx Va ;Va now contains RPS
>
> ldd Va
> cpd #10
> bge output1
> ldaa #00
> output1 ldd Va ;checks value of tens place of RPS
> ldx #10
> idiv
> stx tensplace
> ldd tensplace
> cpd #1
> beq one1
> ldd tensplace
> cpd #2
> beq two1
> ldd tensplace
> cpd #3
> beq three1
> ldd tensplace
> cpd #4
> beq four1
> ldd tensplace
> cpd #5
> beq five1
> ldd tensplace
> cpd #6
> beq six1
> ldd tensplace
> cpd #7
> beq seven1
> ldd tensplace
> cpd #8
> beq eight1
> ldd tensplace
> beq nine1
> ldaa #00
>
> one1 ldaa one ;will load appropriate hex number to
> have 7-seg display output
> two1 ldaa two ;appropriate number
> three1 ldaa three
> four1 ldaa four
> five1 ldaa five
> six1 ldaa six
> seven1 ldaa seven
> eight1 ldaa eight
> nine1 ldaa nine
> staa tensplace
>
> ldd Va ;checks value of tens place of RPS
> ldx #10
> idiv
> stx onesplace
> ldd onesplace
> cpd #1
> beq one2
> ldd onesplace
> cpd #2
> beq two2
> ldd onesplace
> cpd #3
> beq three2
> ldd onesplace
> cpd #4
> beq four2
> ldd onesplace
> cpd #5
> beq five2
> ldd onesplace
> cpd #6
> beq six2
> ldd onesplace
> cpd #7
> beq seven2
> ldd onesplace
> cpd #8
> beq eight2
> ldd onesplace
> beq nine1
> ldaa #00
>
> one2 ldaa one ;will load appropriate hex number to
> have 7-seg display output
> two2 ldaa two ;appropriate number
> three2 ldaa three
> four2 ldaa four
> five2 ldaa five
> six2 ldaa six
> seven2 ldaa seven
> eight2 ldaa eight
> nine2 ldaa nine
> staa onesplace
> movb #\$7C, DDRCAN ;configure portcan for output (from
> textbook)
> movb #\$FF, DDRP ;configure portp for output
> movb tensplace, PORTP ;place tens-place output code on
> portp
> movb #\$40, PORTCAN ;activate pcan6 so that led will
> illuminate with tensplace digit
> movb #\$30, PORTCAN ;activate pcan5
> movb onesplace, PORTP ;illuminate ones-place output code
> lbra loop
>
> swi
>
> holder rmb 2
> holder2 rmb 2
> Va rmb 2
> tensplace rmb 1
> onesplace rmb 1
> zero equ \$7E
> one equ \$30
> two equ \$6D
> three equ \$79
> four equ \$33
> five equ \$5B
> six equ \$5F
> seven equ \$70
> eight equ \$7F
> nine equ \$7B
> PORTP equ \$56
> PORTCAN equ \$13E
> DDRCAN equ \$13F
>
>
>
Thank you for the input.

--- In 6..., mjhuslig@... wrote:
>
>
> eight1 ldaa #eight
> bra nine1b
> nine1 ldaa #nine
> nine1b staa tensplace
>
> Then study the instruction set some more.
>
> > 6... wrote:
> >
> > I have code that is not working for the MC68HC12, it takes 0-5V into the
> > ADC and does some math to convert to revolutions per second and outputs
> > to 2 LED's. Could someone analyze the code to tell me in general what
> > might be wrong with the code. Some where I've think I've made a basic
> > mistake, I have not used the ADC before. I get not display on LED's.
> >
> > The code, sorry don't know how to wrap the code with formatting.
> >
> > include 'MC9S12C128.inc'
> >
> >
> > org \$800
> > movb #\$FF, DDRB
> > movb #\$C0, ATDCTL2
> > movb #\$00, ATDCTL3
> > movb #\$00, ATDCTL4
> > ldaa #1
> > Wait deca
> > bne Wait
> > movb #\$20, ATDCTL5
> > ldab ATDDR0H ;AB will hold the input
> >
> > loop clra ;clear AA- AB holds converted input
> > ldab #\$80 ;test data -to be commented out
> > ldx #51 ;relationship between digital number
> > and BCD
> > idiv ;as defined in prelab
> > stx holder ;holder holds the ones place
> > ldaa #10 ;there will be a remainder. Want at
> > least 1 decimal point accuracy
> > mul
> > ldx #51 ;repeat dividing by 51
> > idiv
> > stx holder2 ;holder2 holds the tenths place
> > ldd holder ;what follows is multiplying both the
> > ones and teneths place by (18/5)
> > ldy #18 ;as shown in pre-lab work
> > emul
> > std holder
> > ldd holder2
> > ldy #18
> > emul
> > std holder2
> > ldd holder
> > ldx #5
> > idiv
> > stx holder
> > ldd holder2
> > ldx #5
> > idiv
> > stx holder2
> > ldd holder2 ;we then want to divide holder2
> > (tenths place) by 10 and add it to holder
> > ldx #10 ;in order to get 1 number with which
> > to continue calculation of RSP
> > idiv
> > xgdx
> > std Va
> > ldd #14 ;we want to add 1.4 to Va, per pre-lab
> > work. divide 14 by 10 to achieve this
> > ldx #10
> > idiv
> > stx holder
> > std holder2 ;remainder stored in holder2
> > ldd Va
> > std Va
> > ldd holder2
> > ldx #10
> > idiv
> > ldd Va
> > std Va
> > ldy #2 ;multiply by 2
> > emul
> > std Va
> > ldd #46 ;multiply by .46 = (46/100)
> > ldx #100
> > idiv
> > stx Va ;Va now contains RPS
> >
> > ldd Va
> > cpd #10
> > bge output1
> > ldaa #00
> >
> >
> > output1 ldd Va ;checks value of tens place of RPS
> > ldx #10
> > idiv
> > stx tensplace
> > ldd tensplace
> > cpd #1
> > beq one1
> > ldd tensplace
> > cpd #2
> > beq two1
> > ldd tensplace
> > cpd #3
> > beq three1
> > ldd tensplace
> > cpd #4
> > beq four1
> > ldd tensplace
> > cpd #5
> > beq five1
> > ldd tensplace
> > cpd #6
> > beq six1
> > ldd tensplace
> > cpd #7
> > beq seven1
> > ldd tensplace
> > cpd #8
> > beq eight1
> > ldd tensplace
> > beq nine1
> > ldaa #00
> >
> > one1 ldaa one ;will load appropriate hex number to
> > have 7-seg display output
> > two1 ldaa two ;appropriate number
> > three1 ldaa three
> > four1 ldaa four
> > five1 ldaa five
> > six1 ldaa six
> > seven1 ldaa seven
> > eight1 ldaa eight
> > nine1 ldaa nine
> > staa tensplace
> >
> > ldd Va ;checks value of tens place of RPS
> > ldx #10
> > idiv
> > stx onesplace
> > ldd onesplace
> > cpd #1
> > beq one2
> > ldd onesplace
> > cpd #2
> > beq two2
> > ldd onesplace
> > cpd #3
> > beq three2
> > ldd onesplace
> > cpd #4
> > beq four2
> > ldd onesplace
> > cpd #5
> > beq five2
> > ldd onesplace
> > cpd #6
> > beq six2
> > ldd onesplace
> > cpd #7
> > beq seven2
> > ldd onesplace
> > cpd #8
> > beq eight2
> > ldd onesplace
> > beq nine1
> > ldaa #00
> >
> > one2 ldaa one ;will load appropriate hex number to
> > have 7-seg display output
> > two2 ldaa two ;appropriate number
> > three2 ldaa three
> > four2 ldaa four
> > five2 ldaa five
> > six2 ldaa six
> > seven2 ldaa seven
> > eight2 ldaa eight
> > nine2 ldaa nine
> > staa onesplace
> >
> >
> > movb #\$7C, DDRCAN ;configure portcan for output (from
> > textbook)
> > movb #\$FF, DDRP ;configure portp for output
> > movb tensplace, PORTP ;place tens-place output code on
> > portp
> > movb #\$40, PORTCAN ;activate pcan6 so that led will
> > illuminate with tensplace digit
> > movb #\$30, PORTCAN ;activate pcan5
> > movb onesplace, PORTP ;illuminate ones-place output code
> > lbra loop
> >
> > swi
> >
> >
> >
> > holder rmb 2
> > holder2 rmb 2
> > Va rmb 2
> > tensplace rmb 1
> > onesplace rmb 1
> > zero equ \$7E
> > one equ \$30
> > two equ \$6D
> > three equ \$79
> > four equ \$33
> > five equ \$5B
> > six equ \$5F
> > seven equ \$70
> > eight equ \$7F
> > nine equ \$7B
> > PORTP equ \$56
> > PORTCAN equ \$13E
> > DDRCAN equ \$13F
> >
> >
> >
> >
> >
> >
> >
> >
> >
> >
>