I hooked up a potentiometer fine to my BX24 and I have that running fine but now I am having problems trying to measure the resistance of a Cds. I guess this is more of a shortcoming of my knowledge of electronics but how exactly does the GetADC function work? The potentiometer has 3 different inputs but how would i just measure the resistance of just a regular resistor? Any help would be greatly appreciated. 

using GetADC to measure resistance
Started by ●January 17, 2005
Reply by ●January 17, 200520050117
The BX24 doesn't actually measure resistance, but it does measure voltage
and time. Initially, you used the potentiometer as a voltage divider. One side to +5, the opposite side to ground. The third leg changed voltage as you adjusted the pot. For example: As you turned the pot, the resistance between the leg (attached to BX24) and the voltage supply decreased while the resistance between the leg and ground increased. The sum of both resistors would remain constant  that depend on your pot. Of course it works the other way when you turn the pot the opposite direction. It works similar with a CdS, except you provide the other resistor. It remains constant while you CdS varys with different light. Measure the resistance with the CdS in light and dark to get an average resistance. Try a resistor in that range and use the ADC to check the voltage that is seen at the junction between the two. Hope that helps, Thad flashsanchez <> wrote: I hooked up a potentiometer fine to my BX24 and I have that running fine but now I am having problems trying to measure the resistance of a Cds. I guess this is more of a shortcoming of my knowledge of electronics but how exactly does the GetADC function work? The potentiometer has 3 different inputs but how would i just measure the resistance of just a regular resistor? Any help would be greatly appreciated.  Yahoo! Groups Links To  

Reply by ●January 18, 200520050118
Wow, thanks. That was extremely helpful and informative. Thank you for your help.  In , Thad Larson <highwayman_33402@y...> wrote: > The BX24 doesn't actually measure resistance, but it does measure voltage and time. > > Initially, you used the potentiometer as a voltage divider. One side to +5, the opposite side to ground. The third leg changed voltage as you adjusted the pot. > > For example: As you turned the pot, the resistance between the leg (attached to BX24) and the voltage supply decreased while the resistance between the leg and ground increased. The sum of both resistors would remain constant  that depend on your pot. Of course it works the other way when you turn the pot the opposite direction. > > It works similar with a CdS, except you provide the other resistor. It remains constant while you CdS varys with different light. Measure the resistance with the CdS in light and dark to get an average resistance. Try a resistor in that range and use the ADC to check the voltage that is seen at the junction between the two. > > Hope that helps, > Thad > > flashsanchez <jsanchez@y...> wrote: > > I hooked up a potentiometer fine to my BX24 and I have that running > fine but now I am having problems trying to measure the resistance of > a Cds. I guess this is more of a shortcoming of my knowledge of > electronics but how exactly does the GetADC function work? The > potentiometer has 3 different inputs but how would i just measure the > resistance of just a regular resistor? Any help would be greatly > appreciated. >  > Yahoo! Groups Links > > To > >  > 