# power consumption of integrated circuit in 0.13µm CMOS technology

Started by May 11, 2007
```Hi all,

currently I am investigating a data sorting algorithm on hardware. The
algorithm was implemented in VHDL and is currently running on a Xilinx
Virtex-II Pro XC2VP70 - FF1704 FPGA. Power consumption is a crucial aspect
in the target application. Therefore I made an analysis with the Xilinx
Virtex-II Pro Web Power Tool (www.xilinx.com) and obtained satisfying
results.

Now I'd like to make an estimation what this circuit would consume on a
comparable ASIC 0.13&#2013266101;m CMOS technology (the FPGA is also based on a 0.13&#2013266101;m
CMOS technology). The target clock frequency is 180 MHz, activity ratio is
15%. Is there any rule of thumb or calculation rule?

Any help is highly appreciated !!!!

Regards    Gero

```
```Geronimo Stempovski wrote:
> Hi all,
>
> currently I am investigating a data sorting algorithm on hardware. The
> algorithm was implemented in VHDL and is currently running on a Xilinx
> Virtex-II Pro XC2VP70 - FF1704 FPGA. Power consumption is a crucial aspect
> in the target application. Therefore I made an analysis with the Xilinx
> Virtex-II Pro Web Power Tool (www.xilinx.com) and obtained satisfying
> results.
>
> Now I'd like to make an estimation what this circuit would consume on a
> comparable ASIC 0.13&#2013266101;m CMOS technology (the FPGA is also based on a 0.13&#2013266101;m
> CMOS technology). The target clock frequency is 180 MHz, activity ratio is
> 15%. Is there any rule of thumb or calculation rule?
>
> Any help is highly appreciated !!!!
>
> Regards    Gero
>
>
power is .5*c*v**2*f*sf.  Sounds like you know everything but C.  So you
would need to synthesize or otherwise get a gate count, assume a load
per gate and go from there.

--
Del Cecchi
"This post is my own and doesn&#2013266066;t necessarily represent IBM&#2013266066;s positions,
strategies or opinions.&#2013266068;
```
```C * F * V^2 = P

There is no "1/2", as you get power when you charge, and also when you
discharge a node.

E=1/2 CFV^2 is appropriate for energy stored in a capacitor, not for the
power dissipated when nodes are switching (Charging AND Dis-charging).

Austin
```
```On Fri, 11 May 2007 14:30:20 +0200, "Geronimo Stempovski"
<geronimo.stempovski@arcor.de> wrote:

>Hi all,
>
>currently I am investigating a data sorting algorithm on hardware. The
>algorithm was implemented in VHDL and is currently running on a Xilinx
>Virtex-II Pro XC2VP70 - FF1704 FPGA. Power consumption is a crucial aspect
>in the target application. Therefore I made an analysis with the Xilinx
>Virtex-II Pro Web Power Tool (www.xilinx.com) and obtained satisfying
>results.
>
>Now I'd like to make an estimation what this circuit would consume on a
>comparable ASIC 0.13&#2013266101;m CMOS technology (the FPGA is also based on a 0.13&#2013266101;m
>CMOS technology). The target clock frequency is 180 MHz, activity ratio is
>15%. Is there any rule of thumb or calculation rule?
>
>Any help is highly appreciated !!!!
>
>Regards    Gero
>

There are several design houses that specialize in flipping fpga
designs to asics. I bet one of them would give you a quick estimate.
Google "fpga asic conversion service" or something like that.

John

```
```If you want to retain the 1/2, then I suggest you use T (for
transition) instead of F (for frequency), in order to avoid the
ambiguity.
A factor of 2 might actually mean something  :-)
Peter Alfke

On May 11, 1:43 pm, Del Cecchi <cecchinos...@us.ibm.com> wrote:
> austin wrote:
> > C * F * V^2 = P
>
> > There is no "1/2", as you get power when you charge, and also when you
> > discharge a node.
>
> > E=1/2 CFV^2 is appropriate for energy stored in a capacitor, not for the
> > power dissipated when nodes are switching (Charging AND Dis-charging).
>
> > Austin
>
> true for clocks but data lines usually only transition one direction per
>   cycle at most.  so conventionally SF=2 for clocks in power calculators.
>
> --
> Del Cecchi
> "This post is my own and doesn't necessarily represent IBM's positions,
> strategies or opinions."

```
```austin wrote:
> C * F * V^2 = P
>
> There is no "1/2", as you get power when you charge, and also when you
> discharge a node.
>
> E=1/2 CFV^2 is appropriate for energy stored in a capacitor, not for the
> power dissipated when nodes are switching (Charging AND Dis-charging).
>
> Austin

true for clocks but data lines usually only transition one direction per
cycle at most.  so conventionally SF=2 for clocks in power calculators.

--
Del Cecchi
"This post is my own and doesn&#2013266066;t necessarily represent IBM&#2013266066;s positions,
strategies or opinions.&#2013266068;
```