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power consumption of integrated circuit in 0.13µm CMOS technology

Started by Geronimo Stempovski May 11, 2007
Hi all,

currently I am investigating a data sorting algorithm on hardware. The 
algorithm was implemented in VHDL and is currently running on a Xilinx 
Virtex-II Pro XC2VP70 - FF1704 FPGA. Power consumption is a crucial aspect 
in the target application. Therefore I made an analysis with the Xilinx 
Virtex-II Pro Web Power Tool (www.xilinx.com) and obtained satisfying 
results.

Now I'd like to make an estimation what this circuit would consume on a 
comparable ASIC 0.13�m CMOS technology (the FPGA is also based on a 0.13�m 
CMOS technology). The target clock frequency is 180 MHz, activity ratio is 
15%. Is there any rule of thumb or calculation rule?

Any help is highly appreciated !!!!

Regards    Gero 


Geronimo Stempovski wrote:
> Hi all, > > currently I am investigating a data sorting algorithm on hardware. The > algorithm was implemented in VHDL and is currently running on a Xilinx > Virtex-II Pro XC2VP70 - FF1704 FPGA. Power consumption is a crucial aspect > in the target application. Therefore I made an analysis with the Xilinx > Virtex-II Pro Web Power Tool (www.xilinx.com) and obtained satisfying > results. > > Now I'd like to make an estimation what this circuit would consume on a > comparable ASIC 0.13�m CMOS technology (the FPGA is also based on a 0.13�m > CMOS technology). The target clock frequency is 180 MHz, activity ratio is > 15%. Is there any rule of thumb or calculation rule? > > Any help is highly appreciated !!!! > > Regards Gero > >
power is .5*c*v**2*f*sf. Sounds like you know everything but C. So you would need to synthesize or otherwise get a gate count, assume a load per gate and go from there. -- Del Cecchi "This post is my own and doesn�t necessarily represent IBM�s positions, strategies or opinions.�
C * F * V^2 = P

There is no "1/2", as you get power when you charge, and also when you
discharge a node.

E=1/2 CFV^2 is appropriate for energy stored in a capacitor, not for the
power dissipated when nodes are switching (Charging AND Dis-charging).

Austin
On Fri, 11 May 2007 14:30:20 +0200, "Geronimo Stempovski"
<geronimo.stempovski@arcor.de> wrote:

>Hi all, > >currently I am investigating a data sorting algorithm on hardware. The >algorithm was implemented in VHDL and is currently running on a Xilinx >Virtex-II Pro XC2VP70 - FF1704 FPGA. Power consumption is a crucial aspect >in the target application. Therefore I made an analysis with the Xilinx >Virtex-II Pro Web Power Tool (www.xilinx.com) and obtained satisfying >results. > >Now I'd like to make an estimation what this circuit would consume on a >comparable ASIC 0.13&#4294967295;m CMOS technology (the FPGA is also based on a 0.13&#4294967295;m >CMOS technology). The target clock frequency is 180 MHz, activity ratio is >15%. Is there any rule of thumb or calculation rule? > >Any help is highly appreciated !!!! > >Regards Gero >
There are several design houses that specialize in flipping fpga designs to asics. I bet one of them would give you a quick estimate. Google "fpga asic conversion service" or something like that. John
If you want to retain the 1/2, then I suggest you use T (for
transition) instead of F (for frequency), in order to avoid the
ambiguity.
A factor of 2 might actually mean something  :-)
Peter Alfke

On May 11, 1:43 pm, Del Cecchi <cecchinos...@us.ibm.com> wrote:
> austin wrote: > > C * F * V^2 = P > > > There is no "1/2", as you get power when you charge, and also when you > > discharge a node. > > > E=1/2 CFV^2 is appropriate for energy stored in a capacitor, not for the > > power dissipated when nodes are switching (Charging AND Dis-charging). > > > Austin > > true for clocks but data lines usually only transition one direction per > cycle at most. so conventionally SF=2 for clocks in power calculators. > > -- > Del Cecchi > "This post is my own and doesn't necessarily represent IBM's positions, > strategies or opinions."
austin wrote:
> C * F * V^2 = P > > There is no "1/2", as you get power when you charge, and also when you > discharge a node. > > E=1/2 CFV^2 is appropriate for energy stored in a capacitor, not for the > power dissipated when nodes are switching (Charging AND Dis-charging). > > Austin
true for clocks but data lines usually only transition one direction per cycle at most. so conventionally SF=2 for clocks in power calculators. -- Del Cecchi "This post is my own and doesn&#4294967295;t necessarily represent IBM&#4294967295;s positions, strategies or opinions.&#4294967295;