Hi, I want to reduce code size of my DSP code. The Infineon TriCore processor I'm using supports two different types of instructions, a 16 and a 32 bit version. There are no equivalent 16bit instructions for all 32bit instruction and the 16bit instructions are obviously more constrained in terms of their operands. So, for example for jumps, the maximal displacement can be 8bit large while the 32bit jumps support up to 16bit. For my question, I however assume that the size of the displacement operand is not an issue. What I want to do in particular is the substitution of 32bit jumps by equivalent 16bit jumps. This is a piece of assembly code I often find in my program and I would like to optimize: move d1, 10 move d2, 1000 jge d2, d1, target So, the constants 10 and 1000 are stored into registers d1 and d2 and finally the jump (jump greater/equal) is taken to "target" if the value of register d2 >= d1. To reduce code size, I'd like to replace this 32bit jump by a 16bit jump which is defined as: jz/jnz dX, target So, whenever the value of register dX is zero (jz) or is not zero (jnz), the branch is taken. Now I'm wondering how the first code can be efficiently transformed into an semantically equal code where jz/jnz is used. Obviously, jz/jnz has a slightly different meaning compared to jge but I hope that there is a way to transform the second code without using too many additional instructions (which would undo the code size reduction I achieve with the jump instruction replacement). A possible solution (but not applicable due to an additional code size increase) could look like: move d1, 10 move d2, 1000 sub d3, d2, d1 ge d4, d2, 0 # d4 becomes 1 if d2 >= 0 jnz d4, target Do you see any better solution. It's fully OK if you give an example in any pseudo assembler code. Thank you. Tim

# Code transformations

Started by ●March 10, 2008