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Hello All, In the Philips document 'UM_LPC21XX_LPC22XX_2.pdf' on page 137 I read: Applications that require instanatneous appearance of zeros and ones on the respected parallel port can use direct access to ports corresponding GPIO Pin Value Register (IOPIN). Assuming that pins P0.8 to P0.15 are configured as output, write to IO0PIN: IO0PIN = 0x0000 C700 will produce the same output as following sequence of writes: IO0SET = 0x0000 C700 IO0CLR = 0x0000 3800 Solution utilizing access to IO0SET and IO0CLR will take more steps compared to a single IO0PIN write access. The same document shows on page 135 that IO#PIN is a ReadOnly register. Am I missing something, how can you write to a ReadOnly register? Best Regards, -- ============================== Aalt Lokhorst Schut Geometrische Meettechniek bv Duinkerkenstraat 21 9723 BN Groningen P.O. Box 5225 9700 GE Groningen The Netherlands Tel: +31-50-5877877 Fax: +31-50-5877899 E-mail: ============================== |
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Writing to IOPIN on LPC21xx possible?
Started by ●January 4, 2005
Reply by ●January 4, 20052005-01-04
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Yes, it's possible...but some people could not agree about the "instantaneous"...;-)) --- In , "Aalt Lokhorst" <lokhorst@s...> wrote: > Hello All, > > In the Philips document 'UM_LPC21XX_LPC22XX_2.pdf' on page 137 I read: > > Applications that require instanatneous appearance of zeros and ones > on the respected parallel port can use direct access to port's > corresponding GPIO Pin Value Register (IOPIN). > Assuming that pins P0.8 to P0.15 are configured as output, write to > IO0PIN: > > IO0PIN = 0x0000 C700 > > will produce the same output as following sequence of writes: > > IO0SET = 0x0000 C700 > IO0CLR = 0x0000 3800 > > Solution utilizing access to IO0SET and IO0CLR will take more steps > compared to a single IO0PIN write access. > > The same document shows on page 135 that IO#PIN is a ReadOnly register. > > Am I missing something, how can you write to a ReadOnly register? > > Best Regards, > > -- ============================== > Aalt Lokhorst > Schut Geometrische Meettechniek bv > Duinkerkenstraat 21 > 9723 BN Groningen > P.O. Box 5225 > 9700 GE Groningen > The Netherlands > Tel: +31-50-5877877 > Fax: +31-50-5877899 > E-mail: Lokhorst@S... > ============================== |
Reply by ●January 4, 20052005-01-04
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I never used IOPIN to set pins. I only use it to read status. This doesn't mean that it is not possible. But it is a good practice to ise IOCLR and IOSET because you are accessing the latches of the pins directly. Consider this, IOPIN=IOPIN|1; this will happen as read-medefy-write now, when you read IOPIN, you are reading the actual state of the pin and if for some reason a load on that pin that caused it to be in the wrong state (it is 1 but was read as 0) that means after read-medify-write, the pin that you didn't want to change got changed. So, only use IOPIN to write not to read-modefy-write, safer. Gus --- In , "Aalt Lokhorst" <lokhorst@s...> wrote: > Hello All, > > In the Philips document 'UM_LPC21XX_LPC22XX_2.pdf' on page 137 I read: > > Applications that require instanatneous appearance of zeros and ones > on the respected parallel port can use direct access to port's > corresponding GPIO Pin Value Register (IOPIN). > Assuming that pins P0.8 to P0.15 are configured as output, write to > IO0PIN: > > IO0PIN = 0x0000 C700 > > will produce the same output as following sequence of writes: > > IO0SET = 0x0000 C700 > IO0CLR = 0x0000 3800 > > Solution utilizing access to IO0SET and IO0CLR will take more steps > compared to a single IO0PIN write access. > > The same document shows on page 135 that IO#PIN is a ReadOnly register. > > Am I missing something, how can you write to a ReadOnly register? > > Best Regards, > > -- ============================== > Aalt Lokhorst > Schut Geometrische Meettechniek bv > Duinkerkenstraat 21 > 9723 BN Groningen > P.O. Box 5225 > 9700 GE Groningen > The Netherlands > Tel: +31-50-5877877 > Fax: +31-50-5877899 > E-mail: Lokhorst@S... > ============================== |
Reply by ●January 5, 20052005-01-05
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Hello Gus and Rodrigo, Thanks for the answer, I was confused by the fact that the IO#PIN register is stated as a ReadOnly register on page 135 of the 'UM_LPC21XX_LPC22XX_2.pdf'. The conclusion is that IO#PIN isn't a ReadOnly register so the information on page 135 is wrong. I am familiar with the Read Modify Write problem. In a 8051 circuit I had some jumpers on a port. Extreme caution was needed to prevent the use of ReadModifyWrite instructions. I noticed the 'instanatneous', it is a copy and paste from the usermanual page 137. Thanks again, -- ============================== Aalt Lokhorst Schut Geometrische Meettechniek bv Duinkerkenstraat 21 9723 BN Groningen P.O. Box 5225 9700 GE Groningen The Netherlands Tel: +31-50-5877877 Fax: +31-50-5877899 E-mail: ============================== |
Reply by ●January 6, 20052005-01-06
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On 4 Jan 2005 at 14:06, Aalt Lokhorst wrote: > > Hello All, > > In the Philips document 'UM_LPC21XX_LPC22XX_2.pdf' on page 137 I read: > > Applications that require instanatneous appearance of zeros and > ones on the respected parallel port can use direct access to ports > corresponding GPIO Pin Value Register (IOPIN). Assuming that pins > P0.8 to P0.15 are configured as output, write to IO0PIN: > > IO0PIN = 0x0000 C700 > > will produce the same output as following sequence of writes: > > IO0SET = 0x0000 C700 > IO0CLR = 0x0000 3800 > > Solution utilizing access to IO0SET and IO0CLR will take more steps > compared to a single IO0PIN write access. > > The same document shows on page 135 that IO#PIN is a ReadOnly > register. > > Am I missing something, how can you write to a ReadOnly register? > Have you received any feedback on this from Philips ? I also notice that IOSET is defined as Read/Write. Why would one want to read the IOSET register. As far as I understand it, If one writes 1 to IOSET, then 1 to IOCLR, the output pin would be 0, but the IOSET register will still indicate a 1, hence making a read from this register meaningless. Regards Anton Erasmus -- A J Erasmus |
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Reply by ●January 7, 20052005-01-07
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Hello Anton Erasmus, No response directly from Philips. But I have to admit that I didn't ask it directly to Philips. I asked it on the forum and I am assuming that Philips is reading it also. Regards Aalt Lokhorst Anton Erasmus wrote: > Have you received any feedback on this from Philips ? I also notice that > IOSET is defined as Read/Write. Why would one want to read the IOSET > register. As far as I understand it, If one writes 1 to IOSET, then 1 to > IOCLR, > the output pin would be 0, but the IOSET register will still indicate a > 1, hence > making a read from this register meaningless. > > Regards > Anton Erasmus > > -- > A J Erasmus |
Reply by ●January 7, 20052005-01-07
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You can write to IOPIN register, if you need ones and zeros appear at the
same time. It works. Apearently just marked as RO in the UM. pin levels change accordingly as stated in the UM when you write to it. Regards, Kerem ----- Original Message ----- From: "Anton Erasmus" <> To: <> Sent: Thursday, January 06, 2005 10:23 PM Subject: Re: [lpc2000] Writing to IOPIN on LPC21xx possible? > > On 4 Jan 2005 at 14:06, Aalt Lokhorst wrote: > >> >> Hello All, >> >> In the Philips document 'UM_LPC21XX_LPC22XX_2.pdf' on page 137 I read: >> >> Applications that require instanatneous appearance of zeros and >> ones on the respected parallel port can use direct access to port's >> corresponding GPIO Pin Value Register (IOPIN). Assuming that pins >> P0.8 to P0.15 are configured as output, write to IO0PIN: >> >> IO0PIN = 0x0000 C700 >> >> will produce the same output as following sequence of writes: >> >> IO0SET = 0x0000 C700 >> IO0CLR = 0x0000 3800 >> >> Solution utilizing access to IO0SET and IO0CLR will take more steps >> compared to a single IO0PIN write access. >> >> The same document shows on page 135 that IO#PIN is a ReadOnly >> register. >> >> Am I missing something, how can you write to a ReadOnly register? >> > > Have you received any feedback on this from Philips ? I also notice that > IOSET is defined as Read/Write. Why would one want to read the IOSET > register. As far as I understand it, If one writes 1 to IOSET, then 1 to > IOCLR, > the output pin would be 0, but the IOSET register will still indicate a 1, > hence > making a read from this register meaningless. > > Regards > Anton Erasmus > > -- > A J Erasmus > > > Yahoo! Groups Links > |
