Hi,,,, every one
I have written a simple progra to perform ADC and simple display using
Printf()..
This is the code
SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI ; // single conversion + interrupt
enable + UNI mode + 256 OSR
SD16AE = SD16AE1; // P1.1 A1+, A1- enable channel
selection
SD16CCTL0 |= SD16SC; // Set bit to start conversion
ofcourse the clock has been setup...
In the ADC interrupt routine what I have done is if the voltage is morethan 0.3V
glow the led and show the result,,id lessthan 0.3V just show the convertedn
Digyal value..
code in Interrupt routine is
if (SD16MEM0 < 0x7FFF) // SD16MEM0 > 0.3V?, clears IFG
{
P1OUT &= ~0x01;
} // bit7 to bit 22 is read by SD16MEMo
since OSR =256,LSBACC=0 and UNI mode
else
{
P1OUT |= 0x01;
printf("%d \n\r",SD16MEM0);
}
so according to the code the full scale voltage is 0 to 0.6V...what I have done
is, applied a DC voltage at ADC pin.. the output digigtal value am getting as
0V.----> 0
0.1V------> 12545
0.2V--------> 25770
0.3 V-------> 260135
0.4V----------> -25413
0.6-----------> -1
How can chage I the configuration to get all posituve Values
Cheers
!!!!!!!!!!!!!!1
How to calibrate ADC
Started by ●February 4, 2009
Reply by ●February 4, 20092009-02-04
Use unsigned format, not signed.
--- In m..., eZ430-Learner wrote:
>
> Hi,,,, every one
>
> I have written a simple progra to perform ADC and simple display
using Printf()..
> This is the code
>
> SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI ; // single conversion +
interrupt enable + UNI mode + 256 OSR
>
> SD16AE = SD16AE1; // P1.1 A1+, A1- enable
channel selection
>
> SD16CCTL0 |= SD16SC; // Set bit to start
conversion
>
> ofcourse the clock has been setup...
>
> In the ADC interrupt routine what I have done is if the voltage is
morethan 0.3V glow the led and show the result,,id lessthan 0.3V just
show the convertedn Digyal value..
>
> code in Interrupt routine is
>
> if (SD16MEM0 < 0x7FFF) // SD16MEM0 > 0.3V?, clears IFG
> {
> P1OUT &= ~0x01;
>
> } // bit7 to bit 22 is read by
SD16MEMo since OSR =256,LSBACC=0 and UNI mode
> else
> {
> P1OUT |= 0x01;
> printf("%d \n\r",SD16MEM0);
> }
>
> so according to the code the full scale voltage is 0 to 0.6V...what
I have done is, applied a DC voltage at ADC pin.. the output digigtal
value am getting as
>
> 0V.----> 0
> 0.1V------> 12545
> 0.2V--------> 25770
> 0.3 V-------> 260135
> 0.4V----------> -25413
> 0.6-----------> -1
>
> How can chage I the configuration to get all posituve Values
>
>
Cheers !!!!!!!!!!!!!!1
>
>
>
>
>
>
>
>
--- In m..., eZ430-Learner wrote:
>
> Hi,,,, every one
>
> I have written a simple progra to perform ADC and simple display
using Printf()..
> This is the code
>
> SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI ; // single conversion +
interrupt enable + UNI mode + 256 OSR
>
> SD16AE = SD16AE1; // P1.1 A1+, A1- enable
channel selection
>
> SD16CCTL0 |= SD16SC; // Set bit to start
conversion
>
> ofcourse the clock has been setup...
>
> In the ADC interrupt routine what I have done is if the voltage is
morethan 0.3V glow the led and show the result,,id lessthan 0.3V just
show the convertedn Digyal value..
>
> code in Interrupt routine is
>
> if (SD16MEM0 < 0x7FFF) // SD16MEM0 > 0.3V?, clears IFG
> {
> P1OUT &= ~0x01;
>
> } // bit7 to bit 22 is read by
SD16MEMo since OSR =256,LSBACC=0 and UNI mode
> else
> {
> P1OUT |= 0x01;
> printf("%d \n\r",SD16MEM0);
> }
>
> so according to the code the full scale voltage is 0 to 0.6V...what
I have done is, applied a DC voltage at ADC pin.. the output digigtal
value am getting as
>
> 0V.----> 0
> 0.1V------> 12545
> 0.2V--------> 25770
> 0.3 V-------> 260135
> 0.4V----------> -25413
> 0.6-----------> -1
>
> How can chage I the configuration to get all posituve Values
>
>
Cheers !!!!!!!!!!!!!!1
>
>
>
>
>
>
>
>
Reply by ●February 4, 20092009-02-04
Is it this bit in control register "SD16CCTL0, SD16_A Control Register 0"
SD16DF Bit 4 SD16_A data format
0---> Offset binary
1----? 2s complement
so code becomes some thing like this
SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI + SD16DF ;
--- On Wed, 2/4/09, old_cow_yellow wrote:
From: old_cow_yellow
Subject: [msp430] Re: How to calibrate ADC
To: m...
Date: Wednesday, February 4, 2009, 9:38 PM
Use unsigned format, not signed.
--- In msp430@yahoogroups. com, eZ430-Learner wrote:
>
> Hi,,,, every one
>
> I have written a simple progra to perform ADC and simple display
using Printf()..
> This is the code
>
> SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI ; // single conversion +
interrupt enable + UNI mode + 256 OSR
>
> SD16AE = SD16AE1; // P1.1 A1+, A1- enable
channel selection
>
> SD16CCTL0 |= SD16SC; // Set bit to start
conversion
>
> ofcourse the clock has been setup...
>
> In the ADC interrupt routine what I have done is if the voltage is
morethan 0.3V glow the led and show the result,,id lessthan 0.3V just
show the convertedn Digyal value..
>
> code in Interrupt routine is
>
> if (SD16MEM0 < 0x7FFF) // SD16MEM0 > 0.3V?, clears IFG
> {
> P1OUT &= ~0x01;
>
> } // bit7 to bit 22 is read by
SD16MEMo since OSR =256,LSBACC= 0 and UNI mode
> else
> {
> P1OUT |= 0x01;
> printf("%d \n\r",SD16MEM0) ;
> }
>
> so according to the code the full scale voltage is 0 to 0.6V...what
I have done is, applied a DC voltage at ADC pin.. the output digigtal
value am getting as
>
> 0V.----> 0
> 0.1V------> 12545
> 0.2V-------- > 25770
> 0.3 V-------> 260135
> 0.4V-------- --> -25413
> 0.6--------- --> -1
>
> How can chage I the configuration to get all posituve Values
>
>
Cheers !!!!!!!!!!!! !!1
>
>
>
>
>
>
>
>
SD16DF Bit 4 SD16_A data format
0---> Offset binary
1----? 2s complement
so code becomes some thing like this
SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI + SD16DF ;
--- On Wed, 2/4/09, old_cow_yellow wrote:
From: old_cow_yellow
Subject: [msp430] Re: How to calibrate ADC
To: m...
Date: Wednesday, February 4, 2009, 9:38 PM
Use unsigned format, not signed.
--- In msp430@yahoogroups. com, eZ430-Learner wrote:
>
> Hi,,,, every one
>
> I have written a simple progra to perform ADC and simple display
using Printf()..
> This is the code
>
> SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI ; // single conversion +
interrupt enable + UNI mode + 256 OSR
>
> SD16AE = SD16AE1; // P1.1 A1+, A1- enable
channel selection
>
> SD16CCTL0 |= SD16SC; // Set bit to start
conversion
>
> ofcourse the clock has been setup...
>
> In the ADC interrupt routine what I have done is if the voltage is
morethan 0.3V glow the led and show the result,,id lessthan 0.3V just
show the convertedn Digyal value..
>
> code in Interrupt routine is
>
> if (SD16MEM0 < 0x7FFF) // SD16MEM0 > 0.3V?, clears IFG
> {
> P1OUT &= ~0x01;
>
> } // bit7 to bit 22 is read by
SD16MEMo since OSR =256,LSBACC= 0 and UNI mode
> else
> {
> P1OUT |= 0x01;
> printf("%d \n\r",SD16MEM0) ;
> }
>
> so according to the code the full scale voltage is 0 to 0.6V...what
I have done is, applied a DC voltage at ADC pin.. the output digigtal
value am getting as
>
> 0V.----> 0
> 0.1V------> 12545
> 0.2V-------- > 25770
> 0.3 V-------> 260135
> 0.4V-------- --> -25413
> 0.6--------- --> -1
>
> How can chage I the configuration to get all posituve Values
>
>
Cheers !!!!!!!!!!!! !!1
>
>
>
>
>
>
>
>
Reply by ●February 4, 20092009-02-04
I barely use C but I think your printf function call could use %u instead of
%d.
Emmett Redd Ph.D. mailto:E...@missouristate.edu
Professor (417)836-5221
Department of Physics, Astronomy, and Materials Science
Missouri State University Fax (417)836-6226
901 SOUTH NATIONAL Dept (417)836-5131
SPRINGFIELD, MO 65897 USA
Physicists always practice energy conservation.
________________________________
From: m... on behalf of eZ430-Learner
Sent: Wed 2/4/2009 9:42 PM
To: m...
Subject: Re: [msp430] Re: How to calibrate ADC
Is it this bit in control register "SD16CCTL0, SD16_A Control Register 0"
SD16DF Bit 4 SD16_A data format
0---> Offset binary
1----? 2s complement
so code becomes some thing like this
SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI + SD16DF ;
--- On Wed, 2/4/09, old_cow_yellow wrote:
From: old_cow_yellow
Subject: [msp430] Re: How to calibrate ADC
To: m...
Date: Wednesday, February 4, 2009, 9:38 PM
Use unsigned format, not signed.
--- In msp430@yahoogroups. com, eZ430-Learner wrote:
>
> Hi,,,, every one
>
> I have written a simple progra to perform ADC and simple display
using Printf()..
> This is the code
>
> SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI ; // single conversion +
interrupt enable + UNI mode + 256 OSR
>
> SD16AE = SD16AE1; // P1.1 A1+, A1- enable
channel selection
>
> SD16CCTL0 |= SD16SC; // Set bit to start
conversion
>
> ofcourse the clock has been setup...
>
> In the ADC interrupt routine what I have done is if the voltage is
morethan 0.3V glow the led and show the result,,id lessthan 0.3V just
show the convertedn Digyal value..
>
> code in Interrupt routine is
>
> if (SD16MEM0 < 0x7FFF) // SD16MEM0 > 0.3V?, clears IFG
> {
> P1OUT &= ~0x01;
>
> } // bit7 to bit 22 is read by
SD16MEMo since OSR =256,LSBACC= 0 and UNI mode
> else
> {
> P1OUT |= 0x01;
> printf("%d \n\r",SD16MEM0) ;
> }
>
> so according to the code the full scale voltage is 0 to 0.6V...what
I have done is, applied a DC voltage at ADC pin.. the output digigtal
value am getting as
>
> 0V.----> 0
> 0.1V------> 12545
> 0.2V-------- > 25770
> 0.3 V-------> 260135
> 0.4V-------- --> -25413
> 0.6--------- --> -1
>
> How can chage I the configuration to get all posituve Values
>
>
Cheers !!!!!!!!!!!! !!1
>
>
>
>
>
>
>
>
Emmett Redd Ph.D. mailto:E...@missouristate.edu
Professor (417)836-5221
Department of Physics, Astronomy, and Materials Science
Missouri State University Fax (417)836-6226
901 SOUTH NATIONAL Dept (417)836-5131
SPRINGFIELD, MO 65897 USA
Physicists always practice energy conservation.
________________________________
From: m... on behalf of eZ430-Learner
Sent: Wed 2/4/2009 9:42 PM
To: m...
Subject: Re: [msp430] Re: How to calibrate ADC
Is it this bit in control register "SD16CCTL0, SD16_A Control Register 0"
SD16DF Bit 4 SD16_A data format
0---> Offset binary
1----? 2s complement
so code becomes some thing like this
SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI + SD16DF ;
--- On Wed, 2/4/09, old_cow_yellow wrote:
From: old_cow_yellow
Subject: [msp430] Re: How to calibrate ADC
To: m...
Date: Wednesday, February 4, 2009, 9:38 PM
Use unsigned format, not signed.
--- In msp430@yahoogroups. com, eZ430-Learner wrote:
>
> Hi,,,, every one
>
> I have written a simple progra to perform ADC and simple display
using Printf()..
> This is the code
>
> SD16CCTL0 = SD16SNGL +SD16IE + SD16UNI ; // single conversion +
interrupt enable + UNI mode + 256 OSR
>
> SD16AE = SD16AE1; // P1.1 A1+, A1- enable
channel selection
>
> SD16CCTL0 |= SD16SC; // Set bit to start
conversion
>
> ofcourse the clock has been setup...
>
> In the ADC interrupt routine what I have done is if the voltage is
morethan 0.3V glow the led and show the result,,id lessthan 0.3V just
show the convertedn Digyal value..
>
> code in Interrupt routine is
>
> if (SD16MEM0 < 0x7FFF) // SD16MEM0 > 0.3V?, clears IFG
> {
> P1OUT &= ~0x01;
>
> } // bit7 to bit 22 is read by
SD16MEMo since OSR =256,LSBACC= 0 and UNI mode
> else
> {
> P1OUT |= 0x01;
> printf("%d \n\r",SD16MEM0) ;
> }
>
> so according to the code the full scale voltage is 0 to 0.6V...what
I have done is, applied a DC voltage at ADC pin.. the output digigtal
value am getting as
>
> 0V.----> 0
> 0.1V------> 12545
> 0.2V-------- > 25770
> 0.3 V-------> 260135
> 0.4V-------- --> -25413
> 0.6--------- --> -1
>
> How can chage I the configuration to get all posituve Values
>
>
Cheers !!!!!!!!!!!! !!1
>
>
>
>
>
>
>
>
