Instruction Set help

Started by February 12, 2010
Hello,
I am very new to the 68HC12. I am in a class where we use the 68HC12 along with an IDE from P&E Microcomputer Systems, Inc. I have only written some basic if-else and while loops at this point. The latest problem I've had is using the instruction FDIV. The code I have so far is:

LDD #\$04
LDX #\$0A
FDIV
STX \$0800 ; the answer I get in acc. X is 6666

I know this is the correct answer since 2^-2 + 2^-3 + 2^-6 + 2^-7 + 2^-10 + 2^-11 + 2^-14 + 2^-15 = .4

I am just wondering how I can multiply numbers by the .4 now? How can I represent .4 in a register?

My goal is to use the number generated by the FDIV, and set it up in a loop to add to itself 10 times. Each time multiplying the result to the slope of a line...

something like:
.4(250) = 100 ----> store in memory \$5000 and \$6000
.8(250) = 200 ----> store in memory \$5001 and \$6001
1.2(250) = 300 ----> store in memory \$5002 and \$6002
1.6(250) = 400 ----> store in memory \$5003 and \$6003
and so on...

Any help would be great. Thanks!

"jason_terhune" wrote:

> Hello,
> I am very new to the 68HC12. I am in a class where we use the 68HC12 along
> with an IDE from P&E Microcomputer Systems, Inc. I have only written some
> basic if-else and while loops at this point. The latest problem I've had
> is using the instruction FDIV. The code I have so far is:
>
> LDD #\$04
> LDX #\$0A
> FDIV
> STX \$0800 ; the answer I get in acc. X is 6666
>
> I know this is the correct answer since 2^-2 + 2^-3 + 2^-6 + 2^-7 + 2^-10
> + 2^-11 + 2^-14 + 2^-15 = .4

FDIV works like this D*\$10000 / X . \$4000000/\$A00=\$6666
>
> I am just wondering how I can multiply numbers by the .4 now? How can I
> represent .4 in a register?

LDD #multiplier
LDY #\$6666
EMUL ;; 32bit product in Y:D
;; to divide by \$10000 just take upper word of
the product:
STY result
Don't know if I understand your question about representing .4 in register.
If you want it to be something like result of 4 FDIV 10, then 4*\$10000 / 10
>
> My goal is to use the number generated by the FDIV, and set it up in a
> loop to add to itself 10 times. Each time multiplying the result to the
> slope of a line...

This is also not fully clear.

>
> something like:
> .4(250) = 100 ----> store in memory \$5000 and \$6000
> .8(250) = 200 ----> store in memory \$5001 and \$6001
> 1.2(250) = 300 ----> store in memory \$5002 and \$6002
> 1.6(250) = 400 ----> store in memory \$5003 and \$6003
> and so on...
>
> Any help would be great. Thanks!

Edward